14m^2-7m-38=8m^2

Solution for 14m^2-7m-38=8m^2 equation:

14m^2-7m-38=8m^2

We move all terms to the left:

14m^2-7m-38-(8m^2)=0

determiningTheFunctionDomain
14m^2-8m^2-7m-38=0

We add all the numbers together, and all the variables

6m^2-7m-38=0

a = 6; b = -7; c = -38;
Δ = b2-4ac
Δ = -72-4·6·(-38)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-31}{2*6}=\frac{-24}{12}
=-2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+31}{2*6}=\frac{38}{12}
=3+1/6
$